File

mod_test_data/mod_test_data.lua @ 6057:cc665f343690

mod_firewall: SUBSCRIBED: Flip subscription check to match documentation The documentation claims that this condition checks whether the recipient is subscribed to the sender. However, it was using the wrong method, and actually checking whether the sender was subscribed to the recipient. A quick poll of folk suggested that the documentation's approach is the right one, so this should fix the code to match the documentation. This should also fix the bundled anti-spam rules from blocking presence from JIDs that you subscribe do (but don't have a mutual subscription with).
author Matthew Wild <mwild1@gmail.com>
date Fri, 22 Nov 2024 13:50:48 +0000
parent 3357:af824168729a
line wrap: on
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local users = { "fezziwig", "badger", "nupkins", "pumblechook", "rouncewell" };
local host = "localhost";

local id = require "util.id";
local st = require "util.stanza";
local sm = require "core.storagemanager";

-- Return a random number from 1..max excluding n
function random_other(n, max) return ((math.random(1, max-1)+(n-1))%max)+1; end

local new_time;
do
	local _current_time = os.time();
	function new_time()
		_current_time = _current_time + math.random(1, 3600);
		return _current_time;
	end
end

function module.command(arg) --luacheck: ignore arg
	sm.initialize_host(host);
	local archive = sm.open(host, "archive", "archive");

	for _ = 1, 100000 do
		local random = math.random(1, #users);
		local user, contact = users[random], users[random_other(random, #users)];
		local user_jid, contact_jid = user.."@"..host, contact.."@"..host;

		local stanza = st.message({ to = contact_jid, from = user_jid, type="chat" })
			:tag("body"):text(id.long());

		archive:append(user, nil, stanza, new_time(), contact_jid)

		local stanza2 = st.clone(stanza);
		stanza2.attr.from, stanza2.attr.to = stanza.attr.to, stanza.attr.from;
		archive:append(contact, nil, stanza2, new_time(), user_jid)
	end
end