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mod_test_data/mod_test_data.lua @ 6057:cc665f343690
mod_firewall: SUBSCRIBED: Flip subscription check to match documentation
The documentation claims that this condition checks whether the recipient is
subscribed to the sender.
However, it was using the wrong method, and actually checking whether the
sender was subscribed to the recipient.
A quick poll of folk suggested that the documentation's approach is the right
one, so this should fix the code to match the documentation.
This should also fix the bundled anti-spam rules from blocking presence from
JIDs that you subscribe do (but don't have a mutual subscription with).
author | Matthew Wild <mwild1@gmail.com> |
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date | Fri, 22 Nov 2024 13:50:48 +0000 |
parent | 3357:af824168729a |
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local users = { "fezziwig", "badger", "nupkins", "pumblechook", "rouncewell" }; local host = "localhost"; local id = require "util.id"; local st = require "util.stanza"; local sm = require "core.storagemanager"; -- Return a random number from 1..max excluding n function random_other(n, max) return ((math.random(1, max-1)+(n-1))%max)+1; end local new_time; do local _current_time = os.time(); function new_time() _current_time = _current_time + math.random(1, 3600); return _current_time; end end function module.command(arg) --luacheck: ignore arg sm.initialize_host(host); local archive = sm.open(host, "archive", "archive"); for _ = 1, 100000 do local random = math.random(1, #users); local user, contact = users[random], users[random_other(random, #users)]; local user_jid, contact_jid = user.."@"..host, contact.."@"..host; local stanza = st.message({ to = contact_jid, from = user_jid, type="chat" }) :tag("body"):text(id.long()); archive:append(user, nil, stanza, new_time(), contact_jid) local stanza2 = st.clone(stanza); stanza2.attr.from, stanza2.attr.to = stanza.attr.to, stanza.attr.from; archive:append(contact, nil, stanza2, new_time(), user_jid) end end