File

mod_muc_lang/mod_muc_lang.lua @ 6057:cc665f343690

mod_firewall: SUBSCRIBED: Flip subscription check to match documentation The documentation claims that this condition checks whether the recipient is subscribed to the sender. However, it was using the wrong method, and actually checking whether the sender was subscribed to the recipient. A quick poll of folk suggested that the documentation's approach is the right one, so this should fix the code to match the documentation. This should also fix the bundled anti-spam rules from blocking presence from JIDs that you subscribe do (but don't have a mutual subscription with).
author Matthew Wild <mwild1@gmail.com>
date Fri, 22 Nov 2024 13:50:48 +0000
parent 3546:ef5d52ca31bb
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assert(module:depends"muc".rooms, "This module is not required with Prosody >= 0.11");

module:hook("muc-config-form", function(event)
	local room, form = event.room, event.form;
	table.insert(form, {
		name = "muc#roomconfig_lang",
		type = "text-single",
		label = "Natural Language for Room Discussions",
		value = room._data.language,
	});
end);

module:hook("muc-config-submitted", function(event)
	local room, fields, changed = event.room, event.fields, event.changed;
	local new = fields["muc#roomconfig_lang"];
	if new ~= room._data.language then
		room._data.language = new;
		if type(changed) == "table" then
			changed["muc#roomconfig_lang"] = true;
		else
			event.changed = true;
		end
	end
end);

module:hook("muc-disco#info", function (event)
	local room, form, formdata = event.room, event.form, event.formdata;

	table.insert(form, {
		name = "muc#roominfo_lang",
		value = room._data.language,
	});
	formdata["muc#roominfo_lang"] = room._data.language;
end);