File

mod_http_rest/mod_http_rest.lua @ 6057:cc665f343690

mod_firewall: SUBSCRIBED: Flip subscription check to match documentation The documentation claims that this condition checks whether the recipient is subscribed to the sender. However, it was using the wrong method, and actually checking whether the sender was subscribed to the recipient. A quick poll of folk suggested that the documentation's approach is the right one, so this should fix the code to match the documentation. This should also fix the bundled anti-spam rules from blocking presence from JIDs that you subscribe do (but don't have a mutual subscription with).
author Matthew Wild <mwild1@gmail.com>
date Fri, 22 Nov 2024 13:50:48 +0000
parent 2336:79432b859d21
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module:depends"http"

local jid_split = require "util.jid".split;
local jid_prep = require "util.jid".prep;
local stanza = require "util.stanza";
local test_password = require "core.usermanager".test_password;
local b64_decode = require "util.encodings".base64.decode;
local formdecode = require "net.http".formdecode;
local xml = require"util.xml";

local function handle_post(event, path, authed_user)
	local request = event.request;
	local headers = request.headers;
	local body_type = headers.content_type;
	if body_type == "text/xml" and request.body then
        local parsed, err = xml.parse(request.body);
        if parsed then
            module:log("debug", "Sending %s", parsed);
            module:send(parsed);
            return 201;
        end
	else
		return 415;
	end
	return 422;
end

module:provides("http", {
	default_path = "/rest";
	route = {
		["POST"] = handle_post;
		OPTIONS = function(e)
			local headers = e.response.headers;
			headers.allow = "POST";
			headers.accept = "test/xml";
			return 200;
		end;
	}
});