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mod_broadcast/mod_broadcast.lua @ 6057:cc665f343690

mod_firewall: SUBSCRIBED: Flip subscription check to match documentation The documentation claims that this condition checks whether the recipient is subscribed to the sender. However, it was using the wrong method, and actually checking whether the sender was subscribed to the recipient. A quick poll of folk suggested that the documentation's approach is the right one, so this should fix the code to match the documentation. This should also fix the bundled anti-spam rules from blocking presence from JIDs that you subscribe do (but don't have a mutual subscription with).
author Matthew Wild <mwild1@gmail.com>
date Fri, 22 Nov 2024 13:50:48 +0000
parent 1016:9f7c97e55593
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local is_admin = require "core.usermanager".is_admin;
local allowed_senders = module:get_option_set("broadcast_senders", {});
local from_address = module:get_option_string("broadcast_from");

local jid_bare = require "util.jid".bare;

function send_to_online(message)
	local c = 0;
	for hostname, host_session in pairs(hosts) do
		if host_session.sessions then
			for username in pairs(host_session.sessions) do
				c = c + 1;
				message.attr.to = username.."@"..hostname;
				module:send(message);
			end
		end
	end
	return c;
end

function send_message(event)
	local stanza = event.stanza;
	local from = stanza.attr.from;
	if is_admin(from) or allowed_senders:contains(jid_bare(from)) then
		if from_address then
			stanza = st.clone(stanza);
			stanza.attr.from = from_address;
		end
		local c = send_to_online(stanza);
		module:log("debug", "Broadcast stanza from %s to %d online users", from, c);
		return true;
	else
		module:log("warn", "Broadcasting is not allowed for %s", from);
	end
end

module:hook("message/bare", send_message);